3.141 \(\int (a+d x^3) (e+f x^4)^2 \, dx\)

Optimal. Leaf size=45 \[ a e^2 x+\frac {2}{5} a e f x^5+\frac {1}{9} a f^2 x^9+\frac {d \left (e+f x^4\right )^3}{12 f} \]

[Out]

a*e^2*x+2/5*a*e*f*x^5+1/9*a*f^2*x^9+1/12*d*(f*x^4+e)^3/f

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Rubi [A]  time = 0.02, antiderivative size = 45, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, integrand size = 17, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.176, Rules used = {1582, 12, 194} \[ a e^2 x+\frac {2}{5} a e f x^5+\frac {1}{9} a f^2 x^9+\frac {d \left (e+f x^4\right )^3}{12 f} \]

Antiderivative was successfully verified.

[In]

Int[(a + d*x^3)*(e + f*x^4)^2,x]

[Out]

a*e^2*x + (2*a*e*f*x^5)/5 + (a*f^2*x^9)/9 + (d*(e + f*x^4)^3)/(12*f)

Rule 12

Int[(a_)*(u_), x_Symbol] :> Dist[a, Int[u, x], x] /; FreeQ[a, x] &&  !MatchQ[u, (b_)*(v_) /; FreeQ[b, x]]

Rule 194

Int[((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Int[ExpandIntegrand[(a + b*x^n)^p, x], x] /; FreeQ[{a, b}, x]
&& IGtQ[n, 0] && IGtQ[p, 0]

Rule 1582

Int[(Px_)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[(Coeff[Px, x, n - 1]*(a + b*x^n)^(p + 1))/(b*n*(p +
1)), x] + Int[(Px - Coeff[Px, x, n - 1]*x^(n - 1))*(a + b*x^n)^p, x] /; FreeQ[{a, b}, x] && PolyQ[Px, x] && I
GtQ[p, 1] && IGtQ[n, 1] && NeQ[Coeff[Px, x, n - 1], 0] && NeQ[Px, Coeff[Px, x, n - 1]*x^(n - 1)] &&  !MatchQ[P
x, (Qx_.)*((c_) + (d_.)*x^(m_))^(q_) /; FreeQ[{c, d}, x] && PolyQ[Qx, x] && IGtQ[q, 1] && IGtQ[m, 1] && NeQ[Co
eff[Qx*(a + b*x^n)^p, x, m - 1], 0] && GtQ[m*q, n*p]]

Rubi steps

\begin {align*} \int \left (a+d x^3\right ) \left (e+f x^4\right )^2 \, dx &=\frac {d \left (e+f x^4\right )^3}{12 f}+\int a \left (e+f x^4\right )^2 \, dx\\ &=\frac {d \left (e+f x^4\right )^3}{12 f}+a \int \left (e+f x^4\right )^2 \, dx\\ &=\frac {d \left (e+f x^4\right )^3}{12 f}+a \int \left (e^2+2 e f x^4+f^2 x^8\right ) \, dx\\ &=a e^2 x+\frac {2}{5} a e f x^5+\frac {1}{9} a f^2 x^9+\frac {d \left (e+f x^4\right )^3}{12 f}\\ \end {align*}

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Mathematica [A]  time = 0.00, size = 60, normalized size = 1.33 \[ a e^2 x+\frac {2}{5} a e f x^5+\frac {1}{9} a f^2 x^9+\frac {1}{4} d e^2 x^4+\frac {1}{4} d e f x^8+\frac {1}{12} d f^2 x^{12} \]

Antiderivative was successfully verified.

[In]

Integrate[(a + d*x^3)*(e + f*x^4)^2,x]

[Out]

a*e^2*x + (d*e^2*x^4)/4 + (2*a*e*f*x^5)/5 + (d*e*f*x^8)/4 + (a*f^2*x^9)/9 + (d*f^2*x^12)/12

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fricas [A]  time = 0.57, size = 50, normalized size = 1.11 \[ \frac {1}{12} x^{12} f^{2} d + \frac {1}{9} x^{9} f^{2} a + \frac {1}{4} x^{8} f e d + \frac {2}{5} x^{5} f e a + \frac {1}{4} x^{4} e^{2} d + x e^{2} a \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((d*x^3+a)*(f*x^4+e)^2,x, algorithm="fricas")

[Out]

1/12*x^12*f^2*d + 1/9*x^9*f^2*a + 1/4*x^8*f*e*d + 2/5*x^5*f*e*a + 1/4*x^4*e^2*d + x*e^2*a

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giac [A]  time = 0.20, size = 50, normalized size = 1.11 \[ \frac {1}{12} \, d f^{2} x^{12} + \frac {1}{9} \, a f^{2} x^{9} + \frac {1}{4} \, d f x^{8} e + \frac {2}{5} \, a f x^{5} e + \frac {1}{4} \, d x^{4} e^{2} + a x e^{2} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((d*x^3+a)*(f*x^4+e)^2,x, algorithm="giac")

[Out]

1/12*d*f^2*x^12 + 1/9*a*f^2*x^9 + 1/4*d*f*x^8*e + 2/5*a*f*x^5*e + 1/4*d*x^4*e^2 + a*x*e^2

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maple [A]  time = 0.04, size = 51, normalized size = 1.13 \[ \frac {1}{12} d \,f^{2} x^{12}+\frac {1}{9} a \,f^{2} x^{9}+\frac {1}{4} d e f \,x^{8}+\frac {2}{5} a e f \,x^{5}+\frac {1}{4} d \,e^{2} x^{4}+a \,e^{2} x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((d*x^3+a)*(f*x^4+e)^2,x)

[Out]

1/12*d*f^2*x^12+1/9*a*f^2*x^9+1/4*d*e*f*x^8+2/5*a*e*f*x^5+1/4*d*e^2*x^4+a*e^2*x

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maxima [A]  time = 1.31, size = 50, normalized size = 1.11 \[ \frac {1}{12} \, d f^{2} x^{12} + \frac {1}{9} \, a f^{2} x^{9} + \frac {1}{4} \, d e f x^{8} + \frac {2}{5} \, a e f x^{5} + \frac {1}{4} \, d e^{2} x^{4} + a e^{2} x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((d*x^3+a)*(f*x^4+e)^2,x, algorithm="maxima")

[Out]

1/12*d*f^2*x^12 + 1/9*a*f^2*x^9 + 1/4*d*e*f*x^8 + 2/5*a*e*f*x^5 + 1/4*d*e^2*x^4 + a*e^2*x

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mupad [B]  time = 0.02, size = 50, normalized size = 1.11 \[ \frac {d\,e^2\,x^4}{4}+a\,e^2\,x+\frac {d\,e\,f\,x^8}{4}+\frac {2\,a\,e\,f\,x^5}{5}+\frac {d\,f^2\,x^{12}}{12}+\frac {a\,f^2\,x^9}{9} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a + d*x^3)*(e + f*x^4)^2,x)

[Out]

(a*f^2*x^9)/9 + (d*e^2*x^4)/4 + (d*f^2*x^12)/12 + a*e^2*x + (2*a*e*f*x^5)/5 + (d*e*f*x^8)/4

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sympy [A]  time = 0.08, size = 58, normalized size = 1.29 \[ a e^{2} x + \frac {2 a e f x^{5}}{5} + \frac {a f^{2} x^{9}}{9} + \frac {d e^{2} x^{4}}{4} + \frac {d e f x^{8}}{4} + \frac {d f^{2} x^{12}}{12} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((d*x**3+a)*(f*x**4+e)**2,x)

[Out]

a*e**2*x + 2*a*e*f*x**5/5 + a*f**2*x**9/9 + d*e**2*x**4/4 + d*e*f*x**8/4 + d*f**2*x**12/12

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